经典线程同步问题（二）

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问题：

编写一个程序，开启3个线程，这3个线程的ID分别为A、B、C，每个线程将自己的ID在屏幕上打印10遍，要求输出结果必须按ABC的顺序显示；如：ABCABC….依次递推。

解答：

在这里我们将题简化为循环打印5遍

HANDLE g_eventA;HANDLE g_eventB;HANDLE g_eventC;unsigned int __stdcall threadFuncA(LPVOID param){ int id = GetCurrentThreadId();for (int i = 0; i<5; ++i){WaitForSingleObject(g_eventA,INFINITE);cout <<"线程ID="<<id<<endl;SetEvent(g_eventB);Sleep(200);}return 0;}unsigned int __stdcall threadFuncB(LPVOID param){ int id = GetCurrentThreadId();for (int i = 0; i<5; ++i){WaitForSingleObject(g_eventB,INFINITE);cout <<"线程ID="<<id<<endl;SetEvent(g_eventC);Sleep(200);}return 0;}unsigned int __stdcall threadFuncC(LPVOID param){ int id = GetCurrentThreadId();for (int i = 0; i<5; ++i){WaitForSingleObject(g_eventC,INFINITE);cout <<"线程ID="<<id<<endl;SetEvent(g_eventA);Sleep(200);}return 0;}int main(int argc, char **argv){g_eventA = CreateEvent(NULL,false,true,NULL);g_eventB = CreateEvent(NULL,false,false,NULL);g_eventC = CreateEvent(NULL,false,false,NULL);HANDLE hdl[3];hdl[0] =(HANDLE)_beginthreadex(NULL,0,threadFuncA,NULL,0,NULL);hdl[1] =(HANDLE)_beginthreadex(NULL,0,threadFuncB,NULL,0,NULL);hdl[2] =(HANDLE)_beginthreadex(NULL,0,threadFuncC,NULL,0,NULL);WaitForMultipleObjects(3,hdl,true,INFINITE);for (int i =0; i<3; ++i){CloseHandle(hdl[i]);}CloseHandle(g_eventA);CloseHandle(g_eventB);CloseHandle(g_eventC);return 0;}

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