【android开发】ANDROID处理JSON格式的数据

来源：互联网发布：spss for mac 23 编辑：程序博客网时间：2024/05/01 10:06

ANDROID处理JSON格式的数据这个例子一定值得收藏。
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
String x;
JSONObject obj;
try {

InputStream is = this.getResources().openRawResource(R.raw.json);
byte [] buffer = new byte[is.available()] ;
is.read(buffer);
TextView v = new TextView(this);

String json = new String(buffer,"utf-8");

obj = new JSONObject(json);

x = obj.getString("姓名");
Log.d("======姓名========",x);
x = obj.getString("性别");
Log.d("======性别========",x);
x = obj.getString("年龄");
Log.d("======年龄========",x);

JSONObject obj1 = obj.getJSONObject("学习成绩");
x = obj1.getString("数学");
Log.d("======数学========",x);
x = obj1.getString("语文");
Log.d("======语文========",x);
x = obj1.getString("英语");
Log.d("======英语========",x);

JSONArray array = obj1.getJSONArray("综合");
obj = array.getJSONObject(0);
x = obj.getString("文科综合");
Log.d("======文科综合========",x);
obj = array.getJSONObject(1);
x = obj.getString("理科综合");
Log.d("======理科综合========",x);

JSONStringer s = new JSONStringer();
Log.d("======================",s.object().key("a").value("aaa").endObject().toString());

} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}

json文件：
{
"姓名":"张三",
"性别":"男",
"年龄":"22",
"学习成绩":
{
"数学":"60",
"语文":"61",
"英语":"62",
"综合":
[
{
"文科综合":"100"
},
{
"理科综合":"110"
}
]
}
}

运行截图：

0 0