求立方根

题目没多大意思，就是考虑问题不够，需要考虑为负数情况

#include<iostream>#include<cstdio>#include<cmath>using namespace std;int main(){double n;int Case;cin >> Case;while( Case-- ){cin >> n;if( n >= 0 ) printf( "%.6lf\n", pow( n, 1.0 / 3 ) );elseprintf( "-%.6lf\n", pow( -n, 1.0/ 3 ) );}return 0;}