CROC-MBTU 2012, Elimination Round / 245D Restoring Table (位运算)
来源:互联网 发布:淘宝退款不退货规则 编辑:程序博客网 时间:2024/05/17 18:15
http://codeforces.com/problemset/problem/245/D
/*30ms,0KB*/#include<bits/stdc++.h>using namespace std;const int mx = 105;int m[mx][mx],a[mx];int main(){int n, i, j;scanf("%d", &n);for (i = 1; i <= n; ++i)for (j = 1; j <= n; ++j)scanf("%d", &m[i][j]);for (i = 1; i <= n; ++i)for (j = 1; j <= n; ++j)if (j != i) a[i] |= m[i][j];printf("%d", a[1]);for (i = 2; i <= n; ++i)printf(" %d", a[i]);putchar(10);return 0;}
0 0
- CROC-MBTU 2012, Elimination Round / 245D Restoring Table (位运算)
- CROC-MBTU 2012, Elimination Round (ACM-ICPC) D题
- CROC-MBTU 2012, Elimination Round (ACM-ICPC)
- CROC-MBTU 2012, Elimination Round (ACM-ICPC)
- CROC-MBTU 2012, Elimination Round (ACM-ICPC)
- CROC-MBTU 2012, Elimination Round (ACM-ICPC)
- CF CROC-MBTU 2012, Elimination Round (ACM-ICPC)
- CROC-MBTU 2012, Elimination Round / 245F Log Stream Analysis (日期处理&二分)
- CROC-MBTU 2012, Elimination Round / 245E Mishap in Club (想法题)
- Restoring Table--CodeForces 245D--位运算
- codeforces CROC-MBTU 2012, Elimination Round (ACM-ICPC) G题 && HDU4039
- CF CROC-MBTU 2012, Final Round div 2
- CROC-MBTU 2012, Final Round (Online version, Div. 2)
- codeforce CROC-MBTU 2012, Final Round (Online version, Div. 2)
- CROC-MBTU 2012, Final Round (Online version, Div. 2)
- CROC 2016 - Elimination Round D 二分+拓扑序+bfs
- Codeforces CROC 2016 - Elimination Round
- CF 245D Restoring Table
- 8. androd中XML文件的解析
- GUID和UUID、CLSID、IID 区别及联系
- CodeCombat-胆怯的辱骂
- 数据存储(一)
- SpringSecurity Filter处理流程
- CROC-MBTU 2012, Elimination Round / 245D Restoring Table (位运算)
- 学习笔记 --- LINUX的同步互斥机制 --- 自旋锁与信号量的区别
- 扩展欧几里得算法&同余方程&模m乘法逆元详解
- 深入理解C语言-----副作用(Side Effect)和顺序点(Sequence Point)
- k-means算法
- 辗转相除法
- 智能家居云平台,准备好突出重围了吗?——第15期中国智能家居主题沙龙顺利在京召开
- 学完java基础的感受
- poj 3126 Prime Path(BFS)