Can you solve this equation?

Can you solve this equation?

Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other)

Total Submission(s) : 19   Accepted Submission(s) : 8

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Problem Description

Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;
Now please try your lucky.

Input

The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);

Output

For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.

Sample Input

2100-4

Sample Output

1.6152No solution!

#include<stdio.h>#include<cmath>#include<math.h>int main(){double n,y,low, head, mid;   //  8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Yscanf("%lf",&n);while (n--){scanf("%lf", &y);low = 0; head = 100;mid = (low + head) / 2.0;while (head-low>1e-9){if (8 *pow( mid , 4) + 7 *pow( mid , 3) + 2 *pow( mid , 2) + 3 * mid + 6 >y)head = mid - 1e-9;elselow = mid + 1e-9;mid = (low + head) / 2.0;}if ((8 * pow(0, 4) + 7 * pow(0, 3) + 2 * pow(0, 2) + 3 * 0 + 6) <= y &&y <= (8 * pow(100, 4) + 7 * pow(100, 3) + 2 * pow(100, 2) + 3 * 100 + 6))printf("%0.4lf\n", mid);elseprintf("No solution!\n");}return 0;}