Can you solve this equation?

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 12908    Accepted Submission(s): 5774

Problem Description

Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;
Now please try your lucky.

 

Input

The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);

 

Output

For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.

 

Sample Input

2100-4

 

Sample Output

1.6152No solution!
#include<stdio.h>double m;double f(double x){return 8*x*x*x*x+7*x*x*x+2*x*x+3*x+6;}int main(){int n;scanf("%d",&n);while(n--){double l,r,s,h;scanf("%lf",&m);if(f(0)<=m&&f(100)>=m){l=0,r=100;while(r-l>1e-7){h=(r+l)/2;s=f(h);if(s>m)r=h;elsel=h;}printf("%.4lf\n",(r+l)/2);}else printf("No solution!\n");}return 0;}