【双循环判断】#2 A. Winner

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The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a player gains or loses a particular number of points. In the course of the game the number of points is registered in the line "name score", where name is a player's name, and score is the number of points gained in this round, which is an integer number. If score is negative, this means that the player has lost in the round. So, if two or more players have the maximum number of points (say, it equals to m) at the end of the game, than wins the one of them who scored at least m points first. Initially each player has 0 points. It's guaranteed that at the end of the game at least one player has a positive number of points.

Input

The first line contains an integer number n (1 ≤ n ≤ 1000), n is the number of rounds played. Then follow nlines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is an integer number between -1000 and 1000, inclusive.

Output

Print the name of the winner.

Sample test(s)
input
3mike 3andrew 5mike 2
output
andrew
input
3andrew 3andrew 2mike 5
output
andrew

依然是得瑟的来一个Python2.7代码^_^

# define some variable  n = int(raw_input())  maxScore = {}  input = []    # n times input  while n > 0:      list = raw_input().split()      input.append(list)      name = list[0]      score = int(list[1])      if maxScore.has_key(name):         maxScore[name] += score      else:         maxScore[name] = score      n -= 1    # find maxScore = ans  ans = 0  for key in maxScore:      ans = max(ans , maxScore[key])    # def to find the time >= ans  def getTime(str):      sum = 0      cnt = 0      for list in input:          name = list[0]          score = int(list[1])          if name == str:             sum += score             if sum >= ans:                return cnt          cnt += 1     # one by one if score == ans  time = 2147483647  for key in maxScore:      if maxScore[key] == ans:         t = getTime(key)         if time > t:            time = t            ansName = key    # output  print ansName

然后是C++：

这道题其实几个循环就好：循环读入咱们就不算了，循环1st判断最高值是哪个，循环2nd找到第一次超过这个最高值的是谁，然后，把他给我扔出去！！！

#include <iostream>#include <map>#include <string.h>#include <algorithm>using namespace std;int score[1010];map<string, int> p1,p2;string name[1010];int main(){    int n,i,j;    while(cin>>n)    {        int m = 0;        for(i = 0;i < n;i ++)        {            cin>>name[i]>>score[i];            p1[name[i]] += score[i];        }        for(i = 0;i < n;i ++)        if(p1[name[i]] > m) m = p1[name[i]];        for(i = 0;i < n;i ++)        {            p2[name[i]] += score[i];            if(p2[name[i]] >= m&&p1[name[i]] == m)            {                cout<<name[i]<<endl;                break;            }        }    }}

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