hdu 1056 HangOver(暴力||打表二分)

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小记:这题我试着打表 将浮点值乘以100存入数组保存下第一次为该值时的序号,在输入一个浮点数时只要使其乘以100然后从数组里读取即可,但是WA了,后来发现应该是四舍五入的原因,个别的值会出现不对。所以我放弃了使用数组。


思路:对于这样的数量级,没什么好说的,就是玩玩而已。我试了下二分,GNUC++交890MS,C++357MS。 


代码:

#include <iostream>#include<math.h>#include <stdlib.h>#include <stdio.h>#include <string.h>using namespace std;#define mst(a,b) memset(a,b,sizeof(a))#define eps 10e-8const int MAX_ = 310;double f[MAX_];int d[MAX_+220];void init(){    f[0] = 0;mst(d,0);    for(int i = 1; ; ++i){        f[i] = f[i-1] + 1.0/(i+1);        if(f[i] >= 5.20)break;    }}int binary(double x){    int left, right;    left = 1; right = 276;    if(x < f[left])return left;    if(x > f[right])return -1;    while(left <= right){        int mid = left + (right - left)/2;        if(fabs(f[mid] - x) < eps)return mid;        if(x > f[mid-1] && x < f[mid])return mid;        if(x > f[mid] && x < f[mid+1])return mid+1;        if(x < f[mid])right = mid-1;        else if(x > f[mid]) left = mid+1;    }    return -1;}int main(){    //freopen("f:\\out.txt","w",stdout);    double n;    init();    //cout<<f[275]<<endl;    while(cin>>n){        if(n < eps)break;        cout<<d[(int)(n*100)]<<" card(s)"<<endl;        /*for(int i = 1; i < 277; ++i){            if(n <= f[i]){                cout<<i<<" card(s)"<<endl;break;            }        }cout<<endl;*/    }    return 0;}


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