HDU -- u Calculate e

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u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 18822    Accepted Submission(s): 8211


Problem Description
A simple mathematical formula for e is



where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
 

Output
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
 

Sample Output
n e- -----------0 11 22 2.53 2.6666666674 2.708333333






[cpp] view plaincopy
  1. //杭电1012  
  2. #include <stdio.h>  
  3. int main (int argc, char **argv)  
  4. {  
  5.   
  6.     printf("n e\n");  
  7.     printf("- -----------\n");  
  8.     printf("0 1\n");  
  9.     printf("1 2\n");  
  10.     printf("2 2.5\n");  
  11.     double result = 2.5 ;  
  12.     double p = 0.5;  
  13.     for (int i = 3; i <= 9; ++ i )  
  14.     {  
  15.         p /= i;  
  16.         result += p;  
  17.         printf("%d %.9f\n", i , result);  
  18.     }  
  19.     return  0;  
  20. }  

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