poj1739之插头DP

Tony's Tour

Time Limit: 1000MS Memory Limit: 30000KTotal Submissions: 3256 Accepted: 1510

Description

A square township has been divided up into n*m(n rows and m columns) square plots (1<=N,M<=8),some of them are blocked, others are unblocked. The Farm is located in the lower left plot and the Market is located in the lower right plot. Tony takes her tour of the township going from Farm to Market by walking through every unblocked plot exactly once. 
Write a program that will count how many unique tours Betsy can take in going from Farm to Market. 

Input

The input contains several test cases. The first line of each test case contain two integer numbers n,m, denoting the number of rows and columns of the farm. The following n lines each contains m characters, describe the farm. A '#' means a blocked square, a '.' means a unblocked square. 
The last test case is followed by two zeros. 

Output

For each test case output the answer on a single line.

Sample Input

2 2....2 3#.....3 4............0 0

Sample Output

114

#include <iostream>#include <cstdio>#include <cstdlib>#include <cstring>#include <string>#include <queue>#include <algorithm>#include <map>#include <cmath>#include <iomanip>#define INF 99999999typedef long long LL;using namespace std;const int MAX=1000+10;const int N=8+10;int n,m,size,index;int mp[N][N],total[2],bit[N];int head[MAX],next[MAX],Hash[MAX];LL dp[2][MAX],state[2][MAX],sum;void Init(){memset(mp,0,sizeof mp);sum=index=0;total[index]=1;dp[index][1]=1;state[index][1]=0;}void HashCalState(LL s,LL num){int pos=s%MAX;for(int i=head[pos];i != -1;i=next[i]){if(state[index][Hash[i]] == s){dp[index][Hash[i]]+=num;return;}}++total[index];state[index][total[index]]=s;dp[index][total[index]]=num;//头插法Hash[size]=total[index];next[size]=head[pos];head[pos]=size++; }void DP(){for(int i=1;i<=n;++i){for(int k=1;k<=total[index];++k)state[index][k]<<=2;//由上一行到本行for(int j=1;j<=m;++j){memset(head,-1,sizeof head);size=0;index=index^1;total[index]=0;for(int k=1;k<=total[index^1];++k){LL s=state[index^1][k];LL num=dp[index^1][k];int p=(s>>bit[j-1])%4;int q=(s>>bit[j])%4;if(!mp[i][j]){if(!p && !q)HashCalState(s,num);}else if(!p && !q){if(!mp[i][j+1] || !mp[i+1][j])continue;s=s+(1<<bit[j-1])+2*(1<<bit[j]);HashCalState(s,num);}else if(!p && q){if(mp[i][j+1])HashCalState(s,num);if(mp[i+1][j]){s=s+q*(1<<bit[j-1])-q*(1<<bit[j]);HashCalState(s,num);}}else if(p && !q){if(mp[i+1][j])HashCalState(s,num);if(mp[i][j+1]){s=s-p*(1<<bit[j-1])+p*(1<<bit[j]);HashCalState(s,num);}}else if(p == 1 && q == 1){int b=1;for(int t=j+1;t<=m;++t){int v=(s>>bit[t])%4;if(v == 1)++b;if(v == 2)--b;if(!b){s=s+(1<<bit[t])-2*(1<<bit[t]);break;}}s=s-(1<<bit[j-1])-(1<<bit[j]);HashCalState(s,num);}else if(p == 2 && q == 2){int b=1;for(int t=j-2;t>=0;--t){int v=(s>>bit[t])%4;if(v == 2)++b;if(v == 1)--b;if(!b){s=s-(1<<bit[t])+2*(1<<bit[t]);break;}}s=s-2*(1<<bit[j-1])-2*(1<<bit[j]);HashCalState(s,num);}else if(p == 2 && q == 1){s=s-2*(1<<bit[j-1])-(1<<bit[j]);HashCalState(s,num);}//else if(p == 1 && q == 1)//不能有回路 }} }for(int i=1;i<=total[index];++i)sum+=dp[index][i];}int main(){char ch;for(int i=0;i<N;++i)bit[i]=i<<1;while(~scanf("%d%d",&n,&m),n+m){Init();for(int i=1;i<=n;++i){getchar();for(int j=1;j<=m;++j){scanf("%c",&ch);mp[i][j]=(ch == '.');}}mp[n+1][1]=mp[n+1][m]=1;DP();printf("%lld\n",sum);}return 0;}