Keep on Truckin'

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 8143    Accepted Submission(s): 5654

Problem Description

Boudreaux and Thibodeaux are on the road again . . .

"Boudreaux, we have to get this shipment of mudbugs to Baton Rouge by tonight!"

"Don't worry, Thibodeaux, I already checked ahead. There are three underpasses and our 18-wheeler will fit through all of them, so just keep that motor running!"

"We're not going to make it, I say!"

So, which is it: will there be a very messy accident on Interstate 10, or is Thibodeaux just letting the sound of his own wheels drive him crazy?

 

Input

Input to this problem will consist of a single data set. The data set will be formatted according to the following description.

The data set will consist of a single line containing 3 numbers, separated by single spaces. Each number represents the height of a single underpass in inches. Each number will be between 0 and 300 inclusive.

 

Output

There will be exactly one line of output. This line will be:

   NO CRASH

if the height of the 18-wheeler is less than the height of each of the underpasses, or:

   CRASH X

otherwise, where X is the height of the first underpass in the data set that the 18-wheeler is unable to go under (which means its height is less than or equal to the height of the 18-wheeler). 
The height of the 18-wheeler is 168 inches.

 

Sample Input

180 160 170

 

Sample Output

CRASH 160

 

Source

South Central USA 2003

其实嘛，这题的意思就是让这三个书去跟168比较，如果比168小就输出咯，如果比他大那么就让一个d累加，当d累加到3的时候，意思就是没有一个数比168要小，那么只能就输出no crash了；

#include <stdio.h>
int main()
{
  int a,b,c,d=0;
  scanf("%d%d%d",&a,&b,&c);
  if(a<168)
    printf("CRASH %d\n",a );
  else 
    d++;
  if(b<168)
  printf("CRASH %d\n",b );
  else 
    d++;
  if(c<168)
    printf("CRASH %d\n",c);
  else 
    d++;
  if(d==3)
    printf("NO CRASH");
  return 0;
}