Keep on Truckin'

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 12301    Accepted Submission(s): 8424

Problem Description

Boudreaux and Thibodeaux are on the road again . . .

"Boudreaux, we have to get this shipment of mudbugs to Baton Rouge by tonight!"

"Don't worry, Thibodeaux, I already checked ahead. There are three underpasses and our 18-wheeler will fit through all of them, so just keep that motor running!"

"We're not going to make it, I say!"

So, which is it: will there be a very messy accident on Interstate 10, or is Thibodeaux just letting the sound of his own wheels drive him crazy?

 

Input

Input to this problem will consist of a single data set. The data set will be formatted according to the following description.

The data set will consist of a single line containing 3 numbers, separated by single spaces. Each number represents the height of a single underpass in inches. Each number will be between 0 and 300 inclusive.

 

Output

There will be exactly one line of output. This line will be:

   NO CRASH

if the height of the 18-wheeler is less than the height of each of the underpasses, or:

   CRASH X

otherwise, where X is the height of the first underpass in the data set that the 18-wheeler is unable to go under (which means its height is less than or equal to the height of the 18-wheeler). 
The height of the 18-wheeler is 168 inches.

 

Sample Input

180 160 170

 

Sample Output

CRASH 160

 

题目意思:如果三个数中有低于或等于168的船就会撞上去,否则就不会相撞.

#include <iostream>using namespace std;int main(){    int h1,h2,h3;    cin>>h1>>h2>>h3;    if(h1>168&&h2>168&&h3>168)    {        cout<<"NO CRASH"<<endl;        return 0;    }    if(h1<=168)    {        cout<<"CRASH "<<h1<<endl;    }    else if(h2<=168)    {        cout<<"CRASH "<<h2<<endl;    }    else    {        cout<<"CRASH "<<h3<<endl;    }    return 0;}