[USACO]Mother's Milk【JAVA】

Mother'sMilk

[笔者CSDN传送阵]：http://blog.csdn.net/u013247524/article/details/24390101

Farmer John has three milking buckets of capacity A, B, and Cliters. Each of the numbers A, B, and C is an integer from 1through 20, inclusive. Initially, buckets A and B are empty whilebucket C is full of milk. Sometimes, FJ pours milk from one bucketto another until the second bucket is filled or the first bucket isempty. Once begun, a pour must be completed, of course. Beingthrifty, no milk may be tossed out.

Write a program to help FJ determine what amounts of milk he canleave in bucket C when he begins with three buckets as above, poursmilk among the buckets for a while, and then notes that bucket A isempty.

PROGRAMNAME: milk3

INPUTFORMAT

A single line with the three integers A, B, and C.

SAMPLEINPUT (file milk3.in)

8 9 10

OUTPUTFORMAT

A single line with a sorted list of all the possible amounts ofmilk that can be in bucket C when bucket A is empty.

SAMPLEOUTPUT (file milk3.out)

1 2 8 9 10

SAMPLEINPUT (file milk3.in)

2 5 10

SAMPLEOUTPUT (file milk3.out)

5 6 7 8 9 10

[java] view plaincopy

1.   
2. import java.io.*;  
3. import java.util.StringTokenizer;  
4. import java.util.Collection;  
5. import java.util.TreeSet;  
6.   
7. public class milk3 {  
8.     public static int A;  
9.     public static int B;  
10.     public static int C;  
11.     public static boolean[][][] found;  
12.     public static Collection set;  
13.       
14.     public static void main(String[] args) throws IOException {  
15.         // Use BufferedReader rather than RandomAccessFile; it's much faster  
16.         BufferedReader f = new BufferedReader(new FileReader("milk3.in"));  
17.         // input file name goes above  
18.         PrintWriter out = new PrintWriter(new BufferedWriter(new FileWriter(  
19.                 "milk3.out")));  
20.           
21.         StringTokenizer st = new StringTokenizer(f.readLine());  
22.           
23.         A = Integer.parseInt(st.nextToken());  
24.         B = Integer.parseInt(st.nextToken());  
25.         C = Integer.parseInt(st.nextToken());  
26.         found = new boolean[A+1][B+1][C+1];  
27.         set = new TreeSet();  
28.           
29.         DFS(0,0,C);  
30.           
31.         int flag = 0;  
32.         for(int i: set){  
33.             if(!(flag == 0)){  
34.                 out.print(" ");  
35.             }else{  
36.                 flag++;  
37.             }  
38.             out.print(i);  
39.         }  
40.         out.println();  
41.           
42.         out.close(); // close the output file  
43.         System.exit(0); // don't omit this!  
44.     }  
45.       
46.     public static void DFS(int a, int b, int c){  
47.         if(!found[a][b][c]){  
48.             found[a][b][c] = true;  
49.             if(a == 0){  
50.                 set.add(c);  
51.             }  
52.             if(a<=B-b)DFS(0,a+b, c);     //A=>B  
53.             else DFS(a-(B-b), B, c);  
54.             if(a<=C-c)DFS(0, b, a+c);        //A=>C  
55.             else DFS(a-(C-c), b, C);  
56.               
57.             if(b<=A-a)DFS(a+b,0, c);     //B=>A  
58.             else DFS(A, b-(A-a), c);  
59.             if(b<=C-c)DFS(a,0, c+b);     //B=>C  
60.             else DFS(a, b-(C-c), C);  
61.               
62.             if(c<=A-a)DFS(a+c,b, 0);     //C=>A  
63.             else DFS(A, b, c-(A-a));  
64.             if(c<=B-b)DFS(a,b+c, 0);     //C=>B  
65.             else DFS(a, B, c-(B-b));  
66.               
67.               
68.         }  
69.     }  
70. }  

AC结果：

USER: Singles Xin [xl1993a1]TASK: milk3LANG: JAVACompiling...Compile: OKExecuting...   Test 1: TEST OK [0.101 secs, 32588 KB]   Test 2: TEST OK [0.122 secs, 30540 KB]   Test 3: TEST OK [0.115 secs, 32588 KB]   Test 4: TEST OK [0.108 secs, 30540 KB]   Test 5: TEST OK [0.108 secs, 30540 KB]   Test 6: TEST OK [0.115 secs, 30540 KB]   Test 7: TEST OK [0.122 secs, 30540 KB]   Test 8: TEST OK [0.115 secs, 31564 KB]   Test 9: TEST OK [0.101 secs, 30540 KB]   Test 10: TEST OK [0.115 secs, 32588 KB]All tests OK.
Your program ('milk3') produced all correct answers!  This is yoursubmission #4 for this problem.  Congratulations!

Here are the test data inputs:

------- test 1 ----2 5 10------- test 2 ----20 20 20------- test 3 ----5 11 15------- test 4 ----2 12 20------- test 5 ----19 4 11------- test 6 ----5 11 13------- test 7 ----3 20 20------- test 8 ----7 16 20------- test 9 ----20 10 9------- test 10 ----7 12 18

Keep up the good work!

Thanks for your submission!

给的答案为c的，就略过了