第十一周项目4-类族设计

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/**程序的版权和版本声明部分：*Copyright(c)2014，烟台大学计算机学院学生*All rights reserved.*文件名称:*作者：田成琳*完成日期：2014  年 5 月 10 日*版本号：v1.0*对任务及求解方法的描述部分：*输入描述：无*问题描述：定义点类Point，并以点类为基类，派生出圆类Cricle，           求圆的面积，并派生出圆柱体类。*程序输出：圆和圆柱体的信息*问题分析：*算法设计：*/#include<iostream>#include<Cmath>using namespace std;const double pi=3.14;class Point //定义坐标点类{public:    Point():x(0),y(0) {};    Point(double x0, double y0):x(x0), y(y0) {};double getX(){return x;}double getY(){return y;}    void PrintPoint(); //输出点的信息protected:    double x,y;   //点的横坐标和纵坐标};void Point::PrintPoint(){    cout<<"Point: ("<<x<<","<<y<<")"<<endl;    //输出点}class Cricle:public Point{public:Cricle(Point pts,Point pte);Cricle(double a,double b,double c,double d){r=sqrt(pow(a-c,2)+pow(b-d,2));}double area();double getR(){return r;}protected:double r;};Cricle::Cricle(Point pts,Point pte){r=sqrt(pow((pts.getX()-pte.getX()),2)+pow((pts.getY()-pte.getY()),2));}double Cricle::area(){return pi*r*r;}class Cylinder:public Cricle{public:Cylinder(double a,double b,double c,double d,double hh): h(hh),Cricle(a,b,c,d){}double area1();double volume();private:double h;};double Cylinder::area1(){return 2*pi*getR()*getR()+2*pi*getR()*h;}double Cylinder::volume(){return pi*getR()*getR()*h;}int main(){double h;Point ps(-2,5),pe(7,9);cout<<"两点为："<<endl;cout<<"1st ";ps.PrintPoint();cout<<"2nd ";pe.PrintPoint();cout<<"以两点距离为半径构成的圆："<<endl;Cricle c(ps,pe);cout<<"圆半径为："<<c.getR()<<endl;cout<<"圆的面积为："<<c.area()<<endl;cout<<"以圆半径为半径构成的圆柱体："<<endl;cout<<"请输入圆柱体的高："<<endl;cin>>h;Cylinder Cy(-2,5,7,9,h);cout<<"圆柱体的表面积为："<<Cy.area1()<<endl;cout<<"圆柱体的体积为："<<Cy.volume()<<endl;return 0;}
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心得体会：派生出的类构造函数必须使用到父类的成员
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