第十一周（项目四）——类族的设计。

来源：互联网发布：彬哥破解软件编辑：程序博客网时间：2024/06/07 04:45
/*    02.*烟台大学计算机学院学生    03.*All right reserved.    04.*文件名称*烟台大学计算机学院学生    05.*All right reserved.    06.*文件名称类族的设计07.*作者：王洪海    08.*完成日期：2013年5月13日    09.*版本号：v1.0    10.*对任务及求解方法的描述部分:类族的设计 11.*我的程序：    12.*/   #include <iostream>using namespace std;class point{public:  point (double x0,double y0):x(x0),y(y0){}  ~point(){}  void setpoint(double ,double);  friend ostream &operator <<(ostream &,point &);protected:  double x;  double y;};void point::setpoint(double x0,double y0){    x=x0;    y=y0;}ostream &operator <<(ostream &output,point &p){    output<<"("<<p.x<<","<<p.y<<")"<<endl;    return output;}class circle:public point{ public:   circle(double x0,double y0,double r0):     point(x0,y0),r(r0){}   ~circle(){}   void setr(double);   double area();   friend ostream &operator <<(ostream &,circle &); protected:   double r;};void circle::setr(double r0){    r=r0;}double circle::area(){    double a;    a=3.14*r*r;    return a;}ostream &operator <<(ostream &output,circle &c){    output<<"heart=("<<c.x<<", "<<c.y<<"), r="<<c.r<<", area="<<c.area( )<<endl;    return output;}class cylinder:public circle{public:  cylinder(double x0,double y0,double r0,double h0):    circle(x0,y0,r0),h(h0){}  ~cylinder(){}  void seth(double );  double area();  double volume();  friend ostream &operator <<(ostream &,cylinder &);protected:  double h;};void cylinder::seth(double h0){    h=h0;}double cylinder::volume(){    double s,t;    s=3.14*r*r;    t=s*h;    return t;}double cylinder::area(){    double a;    a=3.14*r*r*2+2*3.14*r*h;    return a;}ostream &operator <<(ostream &output,cylinder &c){    output<<"herat=("<<c.x<<","<<c.y<<")  r="<<c.r<<endl;    output<<"表面积为："<<c.area()<<"   体积为："<<c.volume()<<endl;    return output;}int main(){    point p1(2,3);    circle c(2,3,4);    cylinder z(2,3,4,5);    cout<<"原点坐标为：";    cout<<p1;    cout<<endl;    cout<<"此圆的圆心，半径，面积为："<<endl;    cout<<c;    cout<<endl;    cout<<"此圆柱体的底面圆心，底面半径，圆柱体体积为："<<endl;    cout<<z;}
运行结果，如下图：
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