将2612转换成时间和周一到周日

来源：互联网发布：贪心算法的应用实例编辑：程序博客网时间：2024/04/26 17:34

<pre class="html" name="code">public class ByteUtil {public static byte[] intToByteArray(int num, int size) {byte[] temp = new byte[size];for (int i = 0; i < size; i++) {temp[i] = (byte) ((num >> 8 * i) & 0xFF);}return temp;}public static byte[] intToByte(int i) {byte[] abyte0 = new byte[4];abyte0[0] = (byte) (0xff & i);abyte0[1] = (byte) ((0xff00 & i) >> 8);abyte0[2] = (byte) ((0xff0000 & i) >> 16);abyte0[3] = (byte) ((0xff000000 & i) >> 24);return abyte0;}public static int bytesToInt(byte[] bytes) {int addr = 0;try {addr = bytes[0] & 0xFF;addr |= ((bytes[1] << 8) & 0xFF00);addr |= ((bytes[2] << 16) & 0xFF0000);addr |= ((bytes[3] << 24) & 0xFF000000);} catch (Exception e) {}return addr;}/** * 1 + 2 + 4 + 8 + 16 + 32 + 64 *  * @param cycle */public static String convertToDay(int cycle) {String[] days = { "周日", "周六", "周五", "周四", "周三", "周二", "周一" };cycle = cycle < 128 ? cycle + 128 : cycle;if (cycle == 128) {return "永不";}if (cycle == 255) {return "每天（周一 周二 周三 周四 周五 周六 周日）";}char[] c = Integer.toBinaryString(cycle).toCharArray();StringBuilder builder = new StringBuilder();for (int i = c.length - 1; i > 0; i--) {if (String.valueOf(c[i]).equals("1")) {builder.append(days[i - 1] + " ");}}return builder.toString();}}

byte[] time = ByteUtil.intToByte(bean.Time);String hour = time[1] < 10 ? "0" + time[1] : "" + time[1];String minute = time[0] < 10 ? "0" + time[0] : "" + time[0];tvAlarmTime.setText(getString(R.string.vibrate_time, hour, minute));

public static byte[] intToByte(int i) {byte[] abyte0 = new byte[4];abyte0[0] = (byte) (0xff & i);abyte0[1] = (byte) ((0xff00 & i) >> 8);abyte0[2] = (byte) ((0xff0000 & i) >> 16);abyte0[3] = (byte) ((0xff000000 & i) >> 24);return abyte0;}

int cycle = bean.Cycle;cycle = cycle < 128 ? cycle + 128 : cycle;char[] c = Integer.toBinaryString(cycle).toCharArray();cbMonday.setChecked(String.valueOf(c[7]).equals("1"));cbTuesday.setChecked(String.valueOf(c[6]).equals("1"));cbWednesday.setChecked(String.valueOf(c[5]).equals("1"));cbThursday.setChecked(String.valueOf(c[4]).equals("1"));cbFriday.setChecked(String.valueOf(c[3]).equals("1"));cbSaturday.setChecked(String.valueOf(c[2]).equals("1"));cbSunday.setChecked(String.valueOf(c[1]).equals("1"));

0 0