HDU2952：Counting Sheep(DFS)

Problem Description

A while ago I had trouble sleeping. I used to lie awake, staring at the ceiling, for hours and hours. Then one day my grandmother suggested I tried counting sheep after I'd gone to bed. As always when my grandmother suggests things, I decided to try it out. The only problem was, there were no sheep around to be counted when I went to bed.


Creative as I am, that wasn't going to stop me. I sat down and wrote a computer program that made a grid of characters, where # represents a sheep, while . is grass (or whatever you like, just not sheep). To make the counting a little more interesting, I also decided I wanted to count flocks of sheep instead of single sheep. Two sheep are in the same flock if they share a common side (up, down, right or left). Also, if sheep A is in the same flock as sheep B, and sheep B is in the same flock as sheep C, then sheeps A and C are in the same flock.


Now, I've got a new problem. Though counting these sheep actually helps me fall asleep, I find that it is extremely boring. To solve this, I've decided I need another computer program that does the counting for me. Then I'll be able to just start both these programs before I go to bed, and I'll sleep tight until the morning without any disturbances. I need you to write this program for me.

 

Input

The first line of input contains a single number T, the number of test cases to follow.

Each test case begins with a line containing two numbers, H and W, the height and width of the sheep grid. Then follows H lines, each containing W characters (either # or .), describing that part of the grid.

 

Output

For each test case, output a line containing a single number, the amount of sheep flock son that grid according to the rules stated in the problem description.

Notes and Constraints
0 < T <= 100
0 < H,W <= 100

 

Sample Input

24 4#.#..#.##.##.#.#3 5###.#..#..#.###

 

Sample Output

63
简单DFS，跟1241挺类似的，貌似还要简单一些
#include<stdio.h>#include<string.h>char map[110][110];int vis[110][110];int w,h;void dfs(int x,int y){if(x<0||y<0||x>=w||y>=h)return;if(vis[x][y])return;if(map[x][y]=='.')return;vis[x][y]=1;dfs(x,y+1);dfs(x,y-1);dfs(x+1,y);dfs(x-1,y);}int main(){int t,cnt;scanf("%d",&t);while(t--){scanf("%d%d",&w,&h);for(int i=0;i<w;++i)scanf("%s",map[i]);memset(vis,0,sizeof(vis));cnt=0;for(int i=0;i<w;++i)for(int j=0;j<h;++j)if(!vis[i][j]&&map[i][j]=='#'){dfs(i,j);cnt++;}printf("%d\n",cnt);}return 0;}