LeetCode Simplify Path

题目：

Given an absolute path for a file (Unix-style), simplify it.

For example,
path = "/home/", => "/home"
path = "/a/./b/../../c/", => "/c"

click to show corner cases.

Corner Cases:

• Did you consider the case where path = "/../"?
  In this case, you should return "/".
• Another corner case is the path might contain multiple slashes '/' together, such as "/home//foo/".
  In this case, you should ignore redundant slashes and return "/home/foo".

class Solution {public:string simplifyPath(string path) {stack<string> t;int n = path.size();int i = 0;while (i < n) {if (path[i] == '/')i++;string s;while (path[i] != '/' && i < n) {s.push_back(path[i]);i++;}if (s == "." || s == "")continue;else if (s == "..")  {if (!t.empty())t.pop();}elset.push(s);}if (t.empty())return "/";string ans;while (!t.empty()) {ans = "/" + t.top() + ans;t.pop();}return ans;}};