linux c++获取路径中的文件名

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#include <string.h>
#include <stdio.h>


void  getName(char* full_name,char * dest);


int main(int argc,char*argv[])
{
    char * path="./zxc/chinamobile/20140623.wav";
    char result[256]={'\0'};
     getName(path,result);
    printf("name is %s\n" , result);




}


void  getName(char* full_name,char * dest)
{
     char*  mn_first = full_name;
     char*  mn_last  = full_name + strlen( full_name );
    if ( strrchr( full_name, '\\' ) != NULL )
        mn_first = strrchr( full_name, '\\' ) + 1;
    else if ( strrchr( full_name, '/' ) != NULL )
        mn_first = strrchr( full_name, '/' ) + 1;
    if ( strrchr( full_name, '.' ) != NULL )
        mn_last = strrchr( full_name, '.' );
    if ( mn_last < mn_first )
        mn_last = full_name + strlen( full_name );
   memmove(dest ,mn_first,(mn_last-mn_first));


}
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