[leetcode] Remove Duplicates from Sorted Array

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

For example,
Given input array A = [1,1,2],

Your function should return length = 2, and A is now [1,2].

思路：重写数组A，用后面的数字将前面重复的数字覆盖

代码：

class Solution {public:    int removeDuplicates(int A[], int n) {        if(n==0) return 0;        int j;        for(int i=1;i<n;i++){            if(A[i]!=A[j]){                j++;                A[j]=A[i];            }        }        return j+1;    }};