hdoj 1196 Lowest Bit
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http://acm.hdu.edu.cn/showproblem.php?pid=1196
Lowest Bit
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7684 Accepted Submission(s): 5641
Problem Description
Given an positive integer A (1 <= A <= 100), output the lowest bit of A.
For example, given A = 26, we can write A in binary form as 11010, so the lowest bit of A is 10, so the output should be 2.
Another example goes like this: given A = 88, we can write A in binary form as 1011000, so the lowest bit of A is 1000, so the output should be 8.
For example, given A = 26, we can write A in binary form as 11010, so the lowest bit of A is 10, so the output should be 2.
Another example goes like this: given A = 88, we can write A in binary form as 1011000, so the lowest bit of A is 1000, so the output should be 8.
Input
Each line of input contains only an integer A (1 <= A <= 100). A line containing "0" indicates the end of input, and this line is not a part of the input data.
Output
For each A in the input, output a line containing only its lowest bit.
Sample Input
26880
Sample Output
28#include<stdio.h>int main(){ int A,i,j,a[]={1,2,4,8,16,32,64,128,256};//100的二进制数是 1100100 while(scanf("%d",&A)&&A!=0) { for(i=0;;i++) { if(A%2==1)break; A=A/2; } printf("%d\n",a[i]); } return 0;}
0 0
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