HDU 1020 Encoding

怎么说呢，发现自己被坑了好几次，因为我没看清楚数据的范围  搞的我数组开小了 贡献了几次WA

我还以为是我理解错题意了，改了多次代码，最后还是第一次的代码，数组开到10005  瞬间AC 有没有 我是不是很笨呢

下面是题目：（不得不说，这是一道很水的题目）

Encoding

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 26250    Accepted Submission(s): 11565

Problem Description

Given a string containing only 'A' - 'Z', we could encode it using the following method: 

1. Each sub-string containing k same characters should be encoded to "kX" where "X" is the only character in this sub-string.

2. If the length of the sub-string is 1, '1' should be ignored.

 

Input

The first line contains an integer N (1 <= N <= 100) which indicates the number of test cases. The next N lines contain N strings. Each string consists of only 'A' - 'Z' and the length is less than 10000.

 

Output

For each test case, output the encoded string in a line.

 

Sample Input

2ABCABBCCC

 

Sample Output

ABCA2B3C

下面是我的AC代码：

#include<stdio.h>int n;int main(){    while(scanf("%d",&n)!=EOF)    {        getchar();        while(n--)        {            char a[10005];            scanf("%s",a);            int sum=0;            for(int i=0;a[i]!='\0';i++)            {                if(a[i]==a[i+1])                    sum++;                else                    if(sum==0)                    {                        printf("%c",a[i]);                        sum=0;                    }                    else                    {                        printf("%d%c",sum+1,a[i]);                        sum=0;                    }            }            printf("\n");        }    }    return 0;}