1058. A+B in Hogwarts (20)

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#include<stdio.h>int main (){    int a[3],b[3],c[3]={200000000,17,29};scanf("%d.%d.%d",&a[0],&a[1],&a[2]);scanf("%d.%d.%d",&b[0],&b[1],&b[2]);int i,temp=0;for (i=2;i>=0;i--){b[i]=b[i]+a[i]+temp;temp=b[i]/c[i];b[i]=b[i]%c[i];}   //  b[0]=b[0]+a[0]+temp;     printf("%d.%d.%d",b[0],b[1],b[2]);return 0;}

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:
3.2.1 10.16.27
Sample Output:
14.1.28

分析

用C输入格式会很方便,其实直接加不用循环都可以了。


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