leetcode->Candy

来源：互联网发布：手机剪切视频的软件编辑：程序博客网时间：2024/05/21 10:32

<span style="font-family: Arial, Helvetica, sans-serif;">每日一刷，强迫学习</span>

There are N children standing in a line. Each child is assigned a rating value.

You are giving candies to these children subjected to the following requirements:

Each child must have at least one candy.
Children with a higher rating get more candies than their neighbors.

What is the minimum candies you must give?

要求：每人至少一颗；高等级的比相邻的糖果多。

注意：同一等级的没有要求。

思路：第一步，每个小朋友发一颗糖果；

第二步，从左向右扫，遇见当前等级比前一个等级高，则当前糖果=前一个糖果+1；

第三步，从右向左扫，遇见当前等级比后一个高，但是糖果数比后一个低，则当前=后一个+1;

代码：

/* * To change this license header, choose License Headers in Project Properties. * To change this template file, choose Tools | Templates * and open the template in the editor. */package children;/** * * @author zhaoyufeng */public class Children {    public int candy(int[] ratings) {        int length = ratings.length;        int candySum = 0;        int[] candyEach = new int[length];        for (int i = 0; i < length; i++) {            candyEach[i] = 1;        }        for (int i = 1; i < length; i++) {            if (ratings[i] > ratings[i - 1]) {                candyEach[i] = candyEach[i - 1] + 1;            }        }        for (int i = length - 2; i >= 0; i--) {            if (ratings[i] > ratings[i + 1] && candyEach[i] <= candyEach[i + 1] ) {                candyEach[i] = candyEach[i + 1] + 1;            }        }        for (int i = 0; i <= length - 1; i++) {            System.out.print(" ratings[" + i + "]=" + ratings[i]);        }        System.out.println();        for (int i = 0; i <= length - 1; i++) {            System.out.print(" candyEach[" + i + "]=" + candyEach[i]);            candySum += candyEach[i];        }        System.out.println();        System.out.println(candySum);        return candySum;    }    /**     * @param args the command line arguments     */    public static void main(String[] args) {        // TODO code application logic here//        int a[] = {1, 2, 2, 4, 2, 1, 45, 3, 23, 2};        int a[] = {1,2,2};        Children child = new Children();        child.candy(a);    }}

0 0