HDU4941Magical Forest(map)
来源:互联网 发布:淘宝店运营视频教程 编辑:程序博客网 时间:2024/05/01 18:26
Problem Description
There is a forest can be seen as N * M grid. In this forest, there is some magical fruits, These fruits can provide a lot of energy, Each fruit has its location(Xi, Yi) and the energy can be provided Ci.
However, the forest will make the following change sometimes:
1. Two rows of forest exchange.
2. Two columns of forest exchange.
Fortunately, two rows(columns) can exchange only if both of them contain fruits or none of them contain fruits.
Your superior attach importance to these magical fruit, he needs to know this forest information at any time, and you as his best programmer, you need to write a program in order to ask his answers quick every time.
However, the forest will make the following change sometimes:
1. Two rows of forest exchange.
2. Two columns of forest exchange.
Fortunately, two rows(columns) can exchange only if both of them contain fruits or none of them contain fruits.
Your superior attach importance to these magical fruit, he needs to know this forest information at any time, and you as his best programmer, you need to write a program in order to ask his answers quick every time.
Input
The input consists of multiple test cases.
The first line has one integer W. Indicates the case number.(1<=W<=5)
For each case, the first line has three integers N, M, K. Indicates that the forest can be seen as maps N rows, M columns, there are K fruits on the map.(1<=N, M<=2*10^9, 0<=K<=10^5)
The next K lines, each line has three integers X, Y, C, indicates that there is a fruit with C energy in X row, Y column. (0<=X<=N-1, 0<=Y<=M-1, 1<=C<=1000)
The next line has one integer T. (0<=T<=10^5)
The next T lines, each line has three integers Q, A, B.
If Q = 1 indicates that this is a map of the row switching operation, the A row and B row exchange.
If Q = 2 indicates that this is a map of the column switching operation, the A column and B column exchange.
If Q = 3 means that it is time to ask your boss for the map, asked about the situation in (A, B).
(Ensure that all given A, B are legal. )
The first line has one integer W. Indicates the case number.(1<=W<=5)
For each case, the first line has three integers N, M, K. Indicates that the forest can be seen as maps N rows, M columns, there are K fruits on the map.(1<=N, M<=2*10^9, 0<=K<=10^5)
The next K lines, each line has three integers X, Y, C, indicates that there is a fruit with C energy in X row, Y column. (0<=X<=N-1, 0<=Y<=M-1, 1<=C<=1000)
The next line has one integer T. (0<=T<=10^5)
The next T lines, each line has three integers Q, A, B.
If Q = 1 indicates that this is a map of the row switching operation, the A row and B row exchange.
If Q = 2 indicates that this is a map of the column switching operation, the A column and B column exchange.
If Q = 3 means that it is time to ask your boss for the map, asked about the situation in (A, B).
(Ensure that all given A, B are legal. )
Output
For each case, you should output "Case #C:" first, where C indicates the case number and counts from 1.
In each case, for every time the boss asked, output an integer X, if asked point have fruit, then the output is the energy of the fruit, otherwise the output is 0.
In each case, for every time the boss asked, output an integer X, if asked point have fruit, then the output is the energy of the fruit, otherwise the output is 0.
Sample Input
13 3 21 1 12 2 253 1 11 1 22 1 23 1 13 2 2
Sample Output
Case #1:121交换的时候用map记录行、列交换后的位置;#include <iostream>#include <stdio.h>#include <string.h>#include <map>using namespace std;int main(){ int t,n,m,k,cnt=1; scanf("%d",&t); while(t--){ scanf("%d%d%d",&n,&m,&k); map<pair<int ,int >,int > mp; map<int ,int > x; map<int ,int > y; int a,b,c; for(int i=0;i<k;i++){ scanf("%d%d%d",&a,&b,&c); mp[make_pair(a,b)]=c; } printf("Case #%d:\n",cnt++); int q,ord ,l,r; scanf("%d",&q); while(q--){ scanf("%d%d%d",&ord,&a,&b); if(ord==1){ if(!x[a]) l=a; if(!x[b]) r=b; x[a]=r,x[b]=l; } if(ord==2){ if(!y[a]) l=a; if(!y[b]) r=b; y[a]=r,y[b]=l; } if(ord==3){ if(x[a]) l=x[a]; else l=a; if(y[b]) r=y[b]; else r=b; printf("%d\n",mp[make_pair(l,r)]); } } } return 0;}
0 0
- HDU4941Magical Forest(map)
- HDU4941Magical Forest (二分+链表优化)
- HDU4941:Magical Forest(map)
- hdu round7 Magical Forest(map)
- hdu 4941 Magical Forest map
- hdu 4941 Magical Forest (map)
- hdu 4941 Magical Forest(Map)
- hdu 4941 Magical Forest (map)
- hdu 4941 Magical Forest map
- hdu 4941 Magical Forest (map容器)
- HDU 4941 Magical Forest 【离散化】【map】
- Hdu 4941 Magical Forest(map+离散化)
- HDU 4941 Magical Forest --STL Map应用
- hdoj 4941 Magical Forest 【STL map】
- hdoj4941Magical Forest【stl map+离散化】
- Forest
- Forest
- hdu 4941 Magical Forest(STL map & 结构体运用)
- const int *p和int * const p的区别(常量指针与指向常量的指针)
- HDOJ题目2502月之数(数学,递推)
- Oracle体系结构
- 资源汇总
- python实现tail -f命令功能
- HDU4941Magical Forest(map)
- hbase scan 类
- 6.2.8 In Action
- hdu-oj 1219 AC Me
- 记录一个程序中的小bug,关于GUI的JTable组件
- Stockbroker Grapevine
- hdu 1051(贪心算法)
- hbase filter类
- Rage(PC) Modding Notes : Console Commands