26英文字母使用频率的大样本分析

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样本：英文世界名著（1000部）

样本容量：1.4亿（包含6918个文件，366M）

#include <stdio.h>#include <stdlib.h>#include <string.h>int CountL[26];int CheckL(char c){    int index;    char i, j;    int flag = 0;    for(i = 'A', j = 'a'; i <= 'Z', j <= 'z'; i++, j++)    {        if(i == c)        {            CountL[i - 65]++;            flag = 1;            break;        }        if(j == c)        {            CountL[j - 97]++;            flag = 1;            break;        }    }    return flag;}long LetterScan(char *filepath){    FILE *fp;    long AllCount = 0;    char c;    if((fp = fopen(filepath, "r")) == NULL)    {        perror("Can't open!");        exit(1);    }    while(!feof(fp))    {        c = fgetc(fp);        if(CheckL(c))        {            AllCount++;        }    }    fclose(fp);    return AllCount;}char *SortL(){    int i, j, t;    char c;    char *Letter;    Letter = (char *)calloc(26, sizeof(char));    for(i = 0; i < 26; i++)    {        Letter[i] = i + 97;    }    for(i = 0; i < 25; i++)    {        for(j = 0; j < 25 - i; j++)        {            if(CountL[j] < CountL[j + 1])            {                t = CountL[j];                c = Letter[j];                CountL[j] = CountL[j + 1];                Letter[j] = Letter[j + 1];                CountL[j + 1] = t;                Letter[j + 1] = c;            }        }    }    return Letter;}int main(){    char *FilePath = "/share/test/doc/test.txt";    int i;    long count = 0;    char *Letter;    Letter = (char *)calloc(26, sizeof(char));    system("rm -rf doc/test.txt");    system("cat doc/*txt > doc/test.txt");    count = LetterScan(FilePath);    Letter = SortL();    printf("测试文本包含有效英文字母总数：%ld\n", count);    for(i = 0; i < 26; i++)    {        printf("%c共出现%d次，概率是%f\n", Letter[i], CountL[i], (float)CountL[i] / count);    }    free(Letter);    return 0;}

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