hdu 1228 A + B map 试用

Problem Description

读入两个小于100的正整数A和B,计算A+B.
需要注意的是:A和B的每一位数字由对应的英文单词给出.

 

Input

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出.

 

Output

对每个测试用例输出1行,即A+B的值.

 

Sample Input

one + two =three four + five six =zero seven + eight nine =zero + zero =

 

Sample Output

39096

#include<string>#include<iostream>#include<map>using namespace std;int main(){    map<string,int>m;    string s ,ans;    int a,b;    m["zero"]=0;    m["one"]=1;    m["two"]=2;    m["three"]=3;    m["four"]=4;    m["five"]=5;    m["six"]=6;    m["seven"]=7;    m["eight"]=8;    m["nine"]=9;    while(cin>>s)    {        a=b=0;        while(s!="+")//觉得控制的较好！            {                a=a*10+m[s];                cin>>s;            }        cin>>s;        while(s!="=")        {            b=b*10+m[s];            cin>>s;        }        if(a==0&&b==0)            break;        else          cout<<a+b<<endl;    }    return 0;}