HDU - 5053 the Sum of Cube
来源:互联网 发布:windows 基础编程 类型 编辑:程序博客网 时间:2024/05/16 10:00
Problem Description
A range is given, the begin and the end are both integers. You should sum the cube of all the integers in the range.
Input
The first line of the input is T(1 <= T <= 1000), which stands for the number of test cases you need to solve.
Each case of input is a pair of integer A,B(0 < A <= B <= 10000),representing the range[A,B].
Each case of input is a pair of integer A,B(0 < A <= B <= 10000),representing the range[A,B].
Output
For each test case, print a line “Case #t: ”(without quotes, t means the index of the test case) at the beginning. Then output the answer – sum the cube of all the integers in the range.
Sample Input
21 32 5
Sample Output
Case #1: 36Case #2: 224
Source
2014 ACM/ICPC Asia Regional Shanghai Online
#include <iostream>#include <cstdio>#include <cstring>#include <algorithm>typedef __int64 ll;using namespace std;int main() { int t, a, b, cas =1 ; scanf("%d", &t); while (t--) { scanf("%d%d", &a, &b); ll sum = 0; for (int i = a; i <= b; i++) sum += (ll)i * i * i; printf("Case #%d: ", cas++); printf("%I64d\n", sum); } return 0;}
1 0
- HDU-#5053 the Sum of Cube
- 【水题】HDU 5053 the Sum of Cube
- HDU - 5053 the Sum of Cube
- HDU 5053 the Sum of Cube
- HDU--5053 the Sum of Cube
- hdu 5053 the Sum of Cube 水题
- HDU-5053 the Sum of Cube
- HDU 5053 the Sum of Cube
- hdu 5053 the Sum of Cube
- 【hdu 5053】the Sum of Cube
- Hdu-5053 the Sum of Cube(水题)
- HDU-5053 the Sum of Cube 签到到到到~
- HDU——5053 the Sum of Cube
- hdu 5053 the Sum of Cube(上海网络赛)
- hdu 5053 the Sum of Cube(水)
- HDU-5053-the Sum of Cube【打表】
- the Sum of Cube
- The Sum of Cube
- linux系统下初试编写汇编程序
- 改变世界的17个等式
- map-hdu 4287-Intelligent IME-想法题
- 滤波器设计指标
- 手把手教你做iOS推送
- HDU - 5053 the Sum of Cube
- 数字信号处理中各种频率关系
- Maze For Robot - UVaLive 4040 dp
- php通过MongoClient扩展连接mongodb库的两点建议
- 学习FPGA的网站推荐
- 浏览器与服务器的交互过程
- 常见算法在实际项目中的应用
- 配置ssh公钥访问oschina
- 三色旗问题