leetcode - Populating Next Right Pointers in Each Node II

来源:互联网 发布:诺基亚6120c软件 编辑:程序博客网 时间:2024/05/01 07:36

Follow up for problem "Populating Next Right Pointers in Each Node".

What if the given tree could be any binary tree? Would your previous solution still work?

Note:

  • You may only use constant extra space.

For example,
Given the following binary tree,

         1       /  \      2    3     / \    \    4   5    7

After calling your function, the tree should look like:

         1 -> NULL       /  \      2 -> 3 -> NULL     / \    \    4-> 5 -> 7 -> NULL

/** * Definition for binary tree with next pointer. * struct TreeLinkNode { *  int val; *  TreeLinkNode *left, *right, *next; *  TreeLinkNode(int x) : val(x), left(NULL), right(NULL), next(NULL) {} * }; */struct TreeLinkNode{int val;TreeLinkNode *left, *right, *next;TreeLinkNode(int x) : val(x), left(NULL), right(NULL), next(NULL) {}};class Solution {public:    void connect(TreeLinkNode *root) {TreeLinkNode *head = NULL;TreeLinkNode *prev = NULL;TreeLinkNode *cur  = root;while(cur != NULL){while(cur != NULL){if(cur->left != NULL){if(prev != NULL){prev->next = cur->left;}else{head = cur->left;}prev = cur->left;}if(cur->right != NULL){if(prev != NULL){prev->next = cur->right;}else{head = cur->right;}prev = cur->right;}cur = cur->next;}cur = head;head = NULL;prev = NULL;}    }};


0 0