Unique Paths

来源:互联网 发布:软件里程碑计划模板 编辑:程序博客网 时间:2024/05/27 21:02

A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below).

The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in the diagram below).

How many possible unique paths are there?


Above is a 3 x 7 grid. How many possible unique paths are there? 

Note: m and n will be at most 100.

 

题意:有一个m * n的二维数组,求出从(0,0)到(m-1,n-1)有多少条路,每次移动只能向下或向右

思路:

dp算法。

dp[i][j] = dp[i - 1][j] + dp[i][j - 1];

代码:

public static int uniquePaths(int m, int n) {        int[][] dp = new int[m][n];        for(int i = 0; i < m; i++)        dp[i][0] = 1;        for(int j = 0; j < n; j++)        dp[0][j] = 1;        for(int i = 1; i < m; i++)        for(int j = 1; j < n; j++)        dp[i][j] = dp[i - 1][j] + dp[i][j - 1];        return dp[m - 1][n - 1];    }


 

0 0
原创粉丝点击