HDUOJ 1039

来源：互联网发布：深圳益讯网络编辑：程序博客网时间：2024/04/30 17:06

#include <iostream>#include <string>#include <algorithm>#include <numeric>using namespace std ;bool isV(char c){ return c == 'a' || c=='e' || c == 'i' || c == 'o' || c == 'u';}bool isPass(string s){int num = 1 ;int flag = 0 ;    for ( int i = 0 ; i < s.size();++i)        {        if (isV[s[i]])        {            flag =  1 ;           break ;        }        }    int cnt1=0 , cnt2=0 ;    if ( s.size() >=3 )    {     for ( int i = 0 ; i < s.size()-2;++i)         for ( int j = 0 ; j < 3 ; ++j)             {             if ( isV(s[i+j])) ++cnt1;             else ++cnt2;             }             if ( cnt1 == 3 || cnt2 == 3)                  return false ;                }     if ( s.size()>=2)      {       for ( int i = 0 ; i < s.size();++i)              if (s[i]== s[i+1] && (s[i] != 'e'|| s[i] != 'o'))                return false ;                   }      if ( flag) return true ;      else return false ;}int main(){string s ;cin >> s ;while(s.compare("end")){if ( isPass(s) )        cout<<"<"<<s<<">"<<" is acceptable."<<endl; else        cout<<"<"<<s<<">"<<" is not acceptable."<<endl;cin >> s ;    }return 0 ;}

一开始想错了以为是三个一样的元音字母或者辅音结果。。。。。

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