自制latex小模板

\documentclass{article}

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\usepackage{amsmath}

\usepackage{listings}

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% will be numbered

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% also try caption instead of title

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\title{Homework 2}

\author{Tao Fu}

\begin{document}

\maketitle

\begin{spacing}{1.5}

\section*{Problem 1}

$x(\alpha) \sim N(x(0)+\alpha R,P(0)+\alpha Q)$. When $\alpha = 10$, $x(10) \sim N(3,0.2)$. Therefore $.P(2.9 < x < 3.0)= 0.0875$.

\lstinputlisting{Problem1.m}

\section*{Problem 2}

\begin{figure}[h!]

\begin{center}

\includegraphics[width=9cm ]{figure2}

\caption{relation between$\beta$ and trajectory center}

\end{center}•

\end{figure}•

From the figure, we can get $R^{'}$:

\begin{align*}

\frac {R^{'}+b} {R^{'}-b} & = \frac {r\Delta\theta_2} {r\Delta\theta_1}\\

=> \quad R^{'} & = \frac {b(\Delta\theta_1 + \Delta\theta_2)} {\Delta\theta_2 - \Delta\theta_1};

\end{align*}

Therefore, $tan(\beta) = \frac {a}{R^{'}} = \frac {a(\Delta\theta_2 - \Delta\theta_1)}{b(\Delta\theta_1 + \Delta\theta_2)}=\frac {au}{b}$.\\

\end{spacing}

\end{document}