杭电acm1002A + B Problem II

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A + B Problem II

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 219914 Accepted Submission(s): 42256

Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

Sample Input

21 2112233445566778899 998877665544332211

Sample Output

Case 1:1 + 2 = 3Case 2:112233445566778899 + 998877665544332211 = 1111111111111111110
C++程序
#include <iostream>#include <string>using namespace std;int main(){    char a[1000],b[1000],c[1001];//定义字符串数组    int i,j=1,n1,n2,T,p=0;//p为进位标志    cin>>T;    while (T--)    {        cin>>a>>b;        n1=strlen(a)-1;        n2=strlen(b)-1;        for (i=0;n1>=0||n2>=0;i++,n1--,n2--)//字符串逆序相加        {            if (n1>=0&&n2>=0)            {                c[i]=a[n1]+b[n2]-'0'+p;            }            if (n1>=0&&n2<0)//当数组1长度大于数组2时            {                c[i]=a[n1]+p;            }            if (n1<0&&n2>=0)//当数组2长度大于数组1时            {                c[i]=b[n2]+p;            }            p=0;            if (c[i]>'9')            {                c[i]=c[i]-10;                p=1;            }        }        cout<<"Case "<<j<<":"<<endl;        cout<<a<<" + "<<b<<" = ";        if (p==1)            cout<<p;//若有进位，则输出        while (i--)        {            cout<<c[i];        }        j++;        if (T>=1)            cout<<endl<<endl;        else            cout<<endl;    }    return 0;}

刚开始用C++，有很多不足，希望多多吐槽！！

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