CSU 1010 water drinking

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1010: Water Drinking

Time Limit: 1 Sec Memory Limit: 128 MB
Submit: 224 Solved: 72
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Description

The Happy Desert is full of sands. There is only a kind of animal called camel living on the Happy Desert. ‘Cause they live here, they need water here. Fortunately, they find a pond which is full of water in the east corner of the desert. Though small, but enough. However, they still need to stand in lines to drink the water in the pond.

Now we mark the pond with number 0, and each of the camels with a specific number, starting from 1. And we use a pair of number to show the two adjacent camels, in which the former number is closer to the pond. There may be more than one lines starting from the pond and ending in a certain camel, but each line is always straight and has no forks.

Input

There’re multiple test cases. In each case, there is a number N (1≤N≤100000) followed by N lines of number pairs presenting the proximate two camels. There are 99999 camels at most.

Output

For each test case, output the camel’s number who is standing in the last position of its line but is closest to the pond. If there are more than one answer, output the one with the minimal number.

Sample Input

10 150 20 11 42 33 551 30 20 10 44 5

Sample Output

14 2本题考查的是并查集。可是现在还不懂那个，就用的邻接链表图，虽然很笨，但索性最后AC了。。。需要注意的是RUNTIME ERROR：   (1)不能用while(true)代替while(scan.hasNext())   (2)Java好像不能像C/C++那样提前定义足够大的数组，要尽量根据读入参数确定数组长度import java.util.ArrayList;import java.util.Scanner;public class Main {private LinkNode first;public Main(){}public Main(int a){first=new LinkNode();first.root=a;}public void Insert(int a){if(first.next==null){first.next=new LinkNode(a);}else{LinkNode temp=first.next;first.next=new LinkNode(a);first.next.next=temp;}}public static int min(int[] a){int m;m=a[0];for(int temp:a){if(temp<m){m=temp;}}return m;}public static void main(String[] args) {// TODO Auto-generated method stubScanner scan=new Scanner(System.in);while(scan.hasNext()){int times=scan.nextInt();Main[] link=new Main[times+1];for(int i=0;i<link.length;i++){link[i]=new Main(i);}for(int i=0;i<times;i++){int a=scan.nextInt();int b=scan.nextInt();link[a].Insert(b);}ArrayList<Integer> num=new ArrayList<Integer>();LinkNode temp=link[0].first;while(temp.next!=null){num.add(temp.next.root);temp=temp.next;}int len=num.size();int[] endnum=new int[len];int[] count=new int[len];for(int i=0;i<len;i++){int f=num.get(i);LinkNode t=link[f].first;int countindex=0;while(t.next!=null){t=link[t.next.root].first;countindex++;}endnum[i]=t.root;count[i]=countindex;}int closest=min(count);ArrayList<Integer> c=new ArrayList<Integer>();for(int i=0;i<len;i++){if(count[i]==closest){c.add(endnum[i]);}}int clen=c.size();int[] result=new int[clen];for(int i=0;i<clen;i++){result[i]=c.get(i);}System.out.println(min(result));}}}class LinkNode{public int root;public LinkNode next;public LinkNode(){}public LinkNode(int a){root=a;next=null;}}

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