Power of Cryptography
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这个题吗,就是说给你,2,16,让你算出2的多少次方是16,就这么简单。。我写的也比较简单。。。引入了一个新东西pow,例如,pow(a,b)他的作用就是计算a的b次方是多少,
注意提交的时候需要用C++来提交
#include <iostream>#include <cstring>#include <cmath>#include <cstdio>using namespace std;double a,b,x;int main(){ while(~scanf("%lf%lf",&a,&b)) { //cout<<b<<endl; x=pow(b,1.0/a); //cout<<b<<" "<<1.0/a*1.0<<endl; cout<<x<<endl; } return 0;}
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