Maximum Product Subarray
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fa看了参考,想法快到了
Find the contiguous subarray within an array (containing at least one number) which has the largest product.
For example, given the array [2,3,-2,4]
,
the contiguous subarray [2,3]
has the largest product =6
和max subarray题一样,只不过需要再保存最小值
class Solution: # @param A, a list of integers # @return an integer def maxProduct(self, A): if len(A)==0: return 0 if len(A)==1: return A[0] max_local = min_local = result = A[0]; for i in range(1,len(A)): new_max = max(max(A[i]*max_local,A[i]),A[i]*min_local) new_min = min(min(A[i]*max_local,A[i]),A[i]*min_local) result = max(result,new_max) max_local, min_local = new_max,new_min return result
class Solution {public: int maxProduct(int A[], int n) { if(A==NULL || n==0) return 0; if(n==1) return A[0]; int max_local = A[0], min_local = A[0], result = A[0]; for (int i=1;i<n;i++){ int new_max = max(max(A[i],A[i]*max_local),A[i]*min_local); int new_min = min(min(A[i],A[i]*max_local),A[i]*min_local); result = max(result, new_max); max_local = new_max; min_local = new_min; } return result; }};
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