Single Number

来源:互联网 发布:势不可挡网络剧在线看 编辑:程序博客网 时间:2024/05/29 15:35
Given an array of integers, every element appears twice except for one. Find that single one.


Note:

Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?


class Solution {public:    int singleNumber(int A[], int n) {        int i;        int res = 0;                for(i=0;i<n;i++) {            res ^= A[i];        }                return res;    }};

使用异或


0 0
原创粉丝点击