POJ2484A Funny Game
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A Funny Game
Time Limit: 1000MS Memory Limit: 65536KTotal Submissions: 4102 Accepted: 2488
Description
Alice and Bob decide to play a funny game. At the beginning of the game they pick n(1 <= n <= 106) coins in a circle, as Figure 1 shows. A move consists in removing one or two adjacent coins, leaving all other coins untouched. At least one coin must be removed. Players alternate moves with Alice starting. The player that removes the last coin wins. (The last player to move wins. If you can't move, you lose.)
Figure 1
Note: For n > 3, we use c1, c2, ..., cn to denote the coins clockwise and if Alice remove c2, then c1 and c3 are NOT adjacent! (Because there is an empty place between c1 and c3.)
Suppose that both Alice and Bob do their best in the game.
You are to write a program to determine who will finally win the game.
Figure 1
Note: For n > 3, we use c1, c2, ..., cn to denote the coins clockwise and if Alice remove c2, then c1 and c3 are NOT adjacent! (Because there is an empty place between c1 and c3.)
Suppose that both Alice and Bob do their best in the game.
You are to write a program to determine who will finally win the game.
Input
There are several test cases. Each test case has only one line, which contains a positive integer n (1 <= n <= 106). There are no blank lines between cases. A line with a single 0 terminates the input.
Output
For each test case, if Alice win the game,output "Alice", otherwise output "Bob".
Sample Input
1230
Sample Output
AliceAliceBob
#include <stdio.h>int main(){ int num; while(~scanf("%d", &num) && num != 0) { if(num >= 3)//必败点,这里有个注意的地方就是,抽取的时候只能抽一个或者两个,而且两个的话必须是连续挨着的,所以找规律的时候一定不要遗漏了这一点,所以当数量大于3时,bob总有办法让alice输 printf("Bob\n"); else printf("Alice\n"); } return 0;}
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