Codeforces Round #286 (Div. 2)B. Mr. Kitayuta's Colorful Graph
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Mr. Kitayuta has just bought an undirected graph consisting of n vertices and m edges. The vertices of the graph are numbered from 1 to n. Each edge, namely edge i, has a color ci, connecting vertex ai and bi.
Mr. Kitayuta wants you to process the following q queries.
In the i-th query, he gives you two integers — ui and vi.
Find the number of the colors that satisfy the following condition: the edges of that color connect vertex ui and vertex vi directly or indirectly.
The first line of the input contains space-separated two integers — n and m (2 ≤ n ≤ 100, 1 ≤ m ≤ 100), denoting the number of the vertices and the number of the edges, respectively.
The next m lines contain space-separated three integers — ai, bi (1 ≤ ai < bi ≤ n) and ci (1 ≤ ci ≤ m). Note that there can be multiple edges between two vertices. However, there are no multiple edges of the same color between two vertices, that is, if i ≠ j, (ai, bi, ci) ≠ (aj, bj, cj).
The next line contains a integer — q (1 ≤ q ≤ 100), denoting the number of the queries.
Then follows q lines, containing space-separated two integers — ui and vi (1 ≤ ui, vi ≤ n). It is guaranteed that ui ≠ vi.
For each query, print the answer in a separate line.
4 51 2 11 2 22 3 12 3 32 4 331 23 41 4
210
5 71 5 12 5 13 5 14 5 11 2 22 3 23 4 251 55 12 51 51 4
11112
Let's consider the first sample.
- Vertex 1 and vertex 2 are connected by color 1 and 2.
- Vertex 3 and vertex 4 are connected by color 3.
- Vertex 1 and vertex 4 are not connected by any single color.
#include <iostream>#include <cstdio>#include <cstdlib>#include <cstring>#include <cmath>#include <algorithm>#include <cctype>#include <queue>#include <vector>#define INF 0x7fffffff#define eps (1e-9)#define lenq 2<<16#define maxn 199999999#define clearto(s,x) memset(s,x,sizeof(s))using namespace std;int n, m, tot=0;int edge[110][110][110]={0};int vis[110];int dfs(int a,int b,int t){ if(edge[a][b][t]==1) return 1; int i; for(i=1;i<=n;i++){ if(edge[a][i][t]==0) continue; if(vis[i]==1) continue; vis[i]=1; if(dfs(i,b,t)==1) return 1; } return 0;}int main(){ //freopen("E:\DATA.txt","r",stdin); //int TT=1,tt=1; scanf("%d",&TT); int i=0,j=0,k=0,t=0; scanf("%d %d",&n,&m); int a,b,c; for(i=1;i<=m;i++){ scanf("%d %d %d",&a,&b,&c); edge[a][b][c]=edge[b][a][c]=1; } scanf("%d",&tot); while(tot--){ scanf("%d %d",&a,&b); int ans=0; for(t=1;t<=m;t++){ clearto(vis,0); vis[a]=1; if(dfs(a,b,t)==1) { ans++; edge[a][b][t]=edge[b][a][t]=1; } } printf("%d\n",ans); } return 0;}
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