CF #286 div 2 B. Mr. Kitayuta's Colorful Graph(dfs)
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Mr. Kitayuta has just bought an undirected graph consisting of n vertices and m edges. The vertices of the graph are numbered from 1 to n. Each edge, namely edge i, has a color ci, connecting vertex ai and bi.
Mr. Kitayuta wants you to process the following q queries.
In the i-th query, he gives you two integers — ui and vi.
Find the number of the colors that satisfy the following condition: the edges of that color connect vertex ui and vertex vi directly or indirectly.
The first line of the input contains space-separated two integers — n and m (2 ≤ n ≤ 100, 1 ≤ m ≤ 100), denoting the number of the vertices and the number of the edges, respectively.
The next m lines contain space-separated three integers — ai, bi (1 ≤ ai < bi ≤ n) and ci (1 ≤ ci ≤ m). Note that there can be multiple edges between two vertices. However, there are no multiple edges of the same color between two vertices, that is, if i ≠ j, (ai, bi, ci) ≠ (aj, bj, cj).
The next line contains a integer — q (1 ≤ q ≤ 100), denoting the number of the queries.
Then follows q lines, containing space-separated two integers — ui and vi (1 ≤ ui, vi ≤ n). It is guaranteed that ui ≠ vi.
For each query, print the answer in a separate line.
4 51 2 11 2 22 3 12 3 32 4 331 23 41 4
210
5 71 5 12 5 13 5 14 5 11 2 22 3 23 4 251 55 12 51 51 4
11112
Let's consider the first sample.
- Vertex 1 and vertex 2 are connected by color 1 and 2.
- Vertex 3 and vertex 4 are connected by color 3.
- Vertex 1 and vertex 4 are not connected by any single color.
#include<iostream>#include<cstdio>#include<cstring>#include<cmath>#include<string>#include<algorithm>#include<cstdlib>#include<set>#include<queue>#include<stack>#include<vector>#include<map>#define N 100010#define Mod 10000007#define lson l,mid,idx<<1#define rson mid+1,r,idx<<1|1#define lc idx<<1#define rc idx<<1|1const double EPS = 1e-11;const double PI = acos ( -1.0 );const double E = 2.718281828;typedef long long ll;const int INF = 1000010;using namespace std;bool G[110][110][110];bool vis[110][110][110];int n,m,q;int s,e,ans;int flag;void dfs(int a,int x){ if(a==e) { ans+=1; flag=0; return ; } for(int i=1; i<=n; i++) { if(!flag) break; if(a==i) continue; if(G[a][i][x]&&!vis[a][i][x]&&flag) { vis[a][i][x]=vis[i][a][x]=1; dfs(i,x); } }}int main(){ //freopen("in.txt","r",stdin); while(cin>>n>>m) { memset(vis,0,sizeof vis); memset(G,0,sizeof G); int mm=m; while(m--) { int a,b,c; scanf("%d%d%d",&a,&b,&c); G[a][b][c]=G[b][a][c]=1; } cin>>q; while(q--) { scanf("%d%d\n",&s,&e); memset(vis,0,sizeof vis); ans=0; for(int i=1; i<=mm; i++) { flag=1; dfs(s,i); } printf("%d\n",ans); } } return 0;}
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