【BestCoder】 HDOJ 5163 Taking Bus

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分类讨论一下就行啦。。。。

#include <iostream>#include <queue> #include <stack> #include <map> #include <set> #include <bitset> #include <cstdio> #include <algorithm> #include <cstring> #include <climits>#include <cstdlib>#include <cmath>#include <time.h>#define maxn 200005#define maxm 400005#define eps 1e-10#define mod 1000000007#define INF 0xi3f3f3f3f#define PI (acos(-1.0))#define lowbit(x) (x&(-x))#define mp make_pair#define ls o<<1#define rs o<<1 | 1#define lson o<<1, L, mid #define rson o<<1 | 1, mid+1, R#define pii pair<int, int>//#pragma comment(linker, "/STACK:16777216")typedef long long LL;typedef unsigned long long ULL;//typedef int LL;using namespace std;LL qpow(LL a, LL b){LL res=1,base=a;while(b){if(b%2)res=res*base;base=base*base;b/=2;}return res;}LL powmod(LL a, LL b){LL res=1,base=a;while(b){if(b%2)res=res*base%mod;base=base*base%mod;b/=2;}return res;}// headint n, m;LL sum[maxn];void read(){    scanf("%d%d", &n, &m), n--;    for(int i = 1; i <= n; i++) {        scanf("%I64d", &sum[i]);    }    for(int i = n+1; i <= 2 * n; i++)        sum[i] = sum[2 * n - i + 1];    for(int i = 1; i <= 2 * n; i++) sum[i] += sum[i-1];    //for(int i = 1; i <= 2 * n; i++) printf("AAA %d\n", sum[i]);}LL calc(int a, int b, int d){    if(a == b) return 0;    //printf("AAA %d %d %d\n", a, b, sum[6]);    if(d == 0) {        if(a < b) return sum[b-1] - sum[a-1];        else {            b = 2 * n - b + 1;            return sum[b] - sum[a-1];        }    }    else {        if(a > b) return sum[a-1] - sum[b-1];        else return sum[b-1] + sum[a-1];    }}void work(){    int now = 1, a, b, t = n + 1;    while(m--) {        int d = 0;        scanf("%d%d", &a, &b);        LL ans;        ans = calc(now, a, d);        if(a < now) d = 1;        ans += calc(a, b, d);        now++;        if(now > t) now -= t;        if(a == b) printf("0\n");        else printf("%I64d\n", ans);    }}int main(void){    int _;    while(scanf("%d", &_)!=EOF) {        while(_--) {            read();            work();        }    }    return 0;}


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