C语言及程序设计初步例程-38 用break和continue改变流程

来源：互联网发布：阿里云网址编辑：程序博客网时间：2024/06/16 08:41

贺老师教学链接 C语言及程序设计初步本课讲解

break语句

#include <stdio.h>int main(){    int s=0, k=1;    while(1)    {        s+=k ;        if (k>=100)            break ;        k=k+1;    }    printf("s = %d\n", s);    return 0;}continue语句#include <stdio.h>int main(){    int i;    for (i=1; i<=10 ; i++)    {        if (i%2==0)            continue;        printf("%d\n", i);    }    return 0;}

趣例：豆豆的每一天

#include <stdio.h>int main(){    char cChioce;        do    {        printf("*  1. 吃饭\n");        printf("*  2. 睡觉\n");        printf("*  3. 打豆豆\n");        printf("*  0. 退出\n");        printf("*  请选择（0-3）：");        scanf("%c", &cChioce);        //选择后的处理        if (cChioce=='1')            printf("我吃吃吃...\n");        else if (cChioce=='2')            printf("我睡觉觉...\n");        else if (cChioce=='3')            printf("我打打打...\n");        else if (cChioce=='0')            break;        else        {            printf("\007选择错误！\n");            continue;        }        printf("恭喜你完成了一项工作！\n");    }    while(1);    return 0;}

未来理想的方案

#include <stdio.h>int main(){    char cChioce;    void eat();    void sleep();    void hitdoudou();    do    {        printf("*  1. 吃饭\n");        printf("*  2. 睡觉\n");        printf("*  3. 打豆豆\n");        printf("*  0. 退出\n");        printf("*  请选择（0-3）：");        scanf("%c", &cChioce);        if (cChioce=='1')            eat();        else if (cChioce=='2')            sleep();        else if (cChioce=='3')            hitdoudou();        else if (cChioce=='0')            break;        else        {            printf("\007选择错误！\n");            continue;        }        printf("恭喜你完成了一项工作！\n");    }    while(1);    return 0;}void eat(){    printf("我吃吃吃... ...\n");}void sleep(){    printf("我睡觉觉... ...\n");}void hitdoudou(){    printf("我打打打... ...\n");}

0 0