获取罗辑思维每天的微信语音(python)

by 伍雪颖

一直喜欢听罗辑思维,不过每天去点那个微信的公众号好麻烦,而且每天听一分钟也不太爽,于是今天突然想把它们全pa下来,合并起来,找时间一次全听完不更好.

于是,开动:

上网找了下,发现已经有一个网站有mp3,于是去爬它的数据(也可以直接去爬罗辑思维官网的数据http://www.ljsw.cc)

http://www.ljsw.cc/forum-39-1.html

获取title和mp3的url:

#coding=utf-8
import re,urllib2

f = file('luoji.txt','w')

def getHtmlCode(url):
    return urllib2.urlopen(url).read()

def getTitle(htmlString):
    regTitle = re.compile("xst\">(.+?) ")
        returnregTitle.findall(htmlString)

def getMp3Url(htmlString):
    regMp3 = re.compile("http(.+?).mp3\'")
        returnregMp3.findall(htmlString)

def getLuojiContent(url):
    htmlCode = getHtmlCode(url)
        titles = getTitle(htmlCode)
        urls = getUrl(htmlCode)
        for i in range(0,len(urls)):
            printtitles[i]
                f.write(titles[i] + '-')
                contentHtml = getHtmlCode(urls[i])
                contents = getMp3Url(contentHtml)
                iflen(contents) > 0:
                    mp3Url = 'http' + contents[0] +'.mp3'
                        print mp3Url
                        f.write(mp3Url + '\n')


if __name__ == '__main__':
    for i in range(1,38):
        printstr(i)
            url = 'http://www.ljsw.cc/forum-39-'+ str(i) + '.html'
            try:
                getLuojiContent(url)
                print'finished: ' + str(i)
            except:
                printstr(i) + ': error!'

下载mp3文件:

#coding=utf-8
import re,urllib2,os

for line in open("luoji.txt"):
    contents = line.split('-')
        url = line[11:len(line)-1]
        cmd = 'curl -O "%s"'% (url)
        os.system(cmd)
        fileName = url.split('/')
        name = fileName[len(fileName) - 1]
        os.rename(name,contents[0] +'.mp3')

合并mp3文件:

from glob import iglob
import shutil
import os

PATH = r'mp3'
destination = open('luoji.mp3','wb')
for filename in iglob(os.path.join(PATH, '*.mp3')):
    shutil.copyfileobj(open(filename, 'rb'), destination)

destination.close()

搞定,于是可以一个个听,也可以合起来听

所有python代码:

github代码

所有mp3文件:

链接: http://pan.baidu.com/s/1nt5L7Pf 密码: 5mrg