poj2967

#include <iostream>#include<cstdio>#include<algorithm>using namespace std;int n,a[1000005];int readin(){    char c;    int ans=0;    while(c=getchar())    {        if(c>='0'&&c<='9')        {            ans=ans*10+c-'0';        }        else break;    }    return ans;}bool ok(int a1,int a2,int a3){    return a1>a3-a2;}bool judge(){    if(n<=3)        return false;    if(ok(a[0],a[1],a[n-1]))        return false;    for(int i=2;i<n;i++)    {        if(ok(a[i-2],a[i-1],a[i]))            return true;    }    return false;}int main(){   n=readin();        for(int i=0;i<n;i++)        {            a[i]=readin();        }        sort(a,a+n);        if(judge())            printf("The set is accepted.\n");        else        printf("The set is rejected.\n");    return 0;}

这一题算是水体，考察输入的

但是似乎只能使用G++，我用c++教了n遍都是runtime limited