[HDU]1.2.3 Balloon Comes!

纯水题，加减乘数。

起初没考虑商为整数的情况，两次WA，自责…

Problem：

Balloon Comes!

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5094 Accepted Submission(s): 1641 

Problem Description

The contest starts now! How excited it is to see balloons floating around. You, one of the best programmers in HDU, can get a very beautiful balloon if only you have solved the very very very... easy problem.
Give you an operator (+,-,*, / --denoting addition, subtraction, multiplication, division respectively) and two positive integers, your task is to output the result.
Is it very easy?
Come on, guy! PLMM will send you a beautiful Balloon right now!
Good Luck!

 

Input

Input contains multiple test cases. The first line of the input is a single integer T (0<T<1000) which is the number of test cases. T test cases follow. Each test case contains a char C (+,-,*, /) and two integers A and B(0<A,B<10000).Of course, we all know that A and B are operands and C is an operator.

 

Output

For each case, print the operation result. The result should be rounded to 2 decimal places If and only if it is not an integer.

 

Sample Input

4+ 1 2- 1 2* 1 2/ 1 2

 

Sample Output

3-120.50

 

Author

lcy

Code：

#include<stdio.h>int main(){    int T,a,b;    char operation[2];    scanf("%d",&T);    while(T--)    {        scanf("%s%d%d",operation,&a,&b);        switch(operation[0])        {            case '+':                printf("%d\n",a+b);                break;            case '-':                printf("%d\n",a-b);                break;            case '*':                printf("%d\n",a*b);                break;            case '/':                if(a%b == 0)                    printf("%d\n",a/b);                else                    printf("%.2lf\n",(double)a/b);                break;        }    }    return 0;}

Tip

如果直接使用

char operation;scanf("%c%d%d",operation,&a,&b);

operation会读取上一行末尾的'\n',进而出错。

我在这里使用了字符串输入解决

char operation[2];

scanf("%s%d%d",operation,&a,&b);

后来发现如下其他办法：

getchar();scanf("%c %d %d",&c,&a,&b);

while(isspace((opnd=getchar())));