hdu 5170 对数的应用

根据　log(a^b) = b*log(a)，可以将溢出的值转换成范围内的值

#include <cstdio>#include <algorithm>#include <cmath>#define eps 1e-8using namespace std;int a , b , c , d;int main ( ){    while ( ~scanf ( "%d%d%d%d" , &a , &b , &c , &d ) )    {        double num1 = b*1.0*log(a*1.0);        double num2 = d*1.0*log(c*1.0);        if ( fabs ( num1 -num2 ) < eps ) puts ("=");        else if ( num1 > num2 + eps ) puts ( ">" );        else puts ( "<" );    }}