三色球分组

从3个红球，5个白球，6个黑球中任意取出8个作为一组进行输出。在每组中可以没有黑球，但必须要有红球和白球。编程实现以上功能。用函数返回其组合数，在函数中打印每组的组合

函数原型为： int Fun (void);

程序运行结果为：

The result:

red:   1 white:   1 black:   6

red:   1 white:   2 black:   5

red:   1 white:   3 black:   4

red:   1 white:   4 black:   3

red:   1 white:   5 black:   2

red:   2 white:   1 black:   5

red:   2 white:   2 black:   4

red:   2 white:   3 black:   3

red:   2 white:   4 black:   2

red:   2 white:   5 black:   1

red:   3 white:   1 black:   4

red:   3 white:   2 black:   3

red:   3 white:   3 black:   2

red:   3 white:   4 black:   1

red:   3 white:   5 black:   0

sum=  15

#include <stdio.h>#include <stdlib.h>int red,white,black;int Fun(void){    int sum=0;    for(red=1;red<=3;red++)    {        for(white=1;white<=5;white++)        {            for(black=0;black<=6;black++)            {                if(red+white+black==8)                {                    printf("red:%4d white:%4d black:%4d\n",red,white,black);                    sum++;                }            }        }    }    return sum;}int main(){    int sum;    printf("The result:\n");    sum=Fun();    printf("sum=%4d\n",sum);    return 0;}