LeetCode Combination Sum II
来源:互联网 发布:上海达观数据公司咋样 编辑:程序博客网 时间:2024/06/10 15:37
Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.
Each number in C may only be used once in the combination.
Note:
- All numbers (including target) will be positive integers.
- Elements in a combination (a1, a2, … , ak) must be in non-descending order. (ie, a1 ≤ a2 ≤ … ≤ ak).
- The solution set must not contain duplicate combinations.
For example, given candidate set 10,1,2,7,6,1,5
and target 8
,
A solution set is: [1, 7]
[1, 2, 5]
[2, 6]
[1, 1, 6]
思路分析:这题和Combination Sum很像,唯一的区别是每个数只能使用一次,只需要dfs传入start参数为当前位置的下一个位置i+1即可,详细分析参见Combination Sum的题解。两题代码几乎一样,只有一行不同。
AC Code
public class Solution { public List<List<Integer>> combinationSum2(int[] num, int target) { //1240 List<List<Integer>> res = new ArrayList<List<Integer>>(); int m = num.length; if(m == 0) return res; Arrays.sort(num); List<Integer> item = new ArrayList<Integer>(); dfs(num, target, 0, item, res); return res; } public void dfs(int[] num, int target, int start, List<Integer> item, List<List<Integer>> res){ if(target == 0){ res.add(new ArrayList<Integer>(item)); return; } if(target < 0) return; for(int i = start; i < num.length; i++){ if(i > start && num[i] == num[i-1]) continue;// avoid duplicate solutions item.add(num[i]); dfs(num, target - num[i], i + 1, item, res); item.remove(item.size() - 1); } } //1255}
0 0
- LeetCode: Combination Sum II
- LeetCode: Combination Sum II
- [LeetCode]Combination Sum II
- LeetCode Combination Sum II
- [Leetcode] Combination Sum II
- [LeetCode] Combination Sum II
- LeetCode Combination Sum II
- [Leetcode] Combination Sum II
- LeetCode: Combination Sum II
- leetcode Combination Sum II
- [LeetCode]Combination Sum II
- [leetcode] Combination Sum II
- LeetCode-Combination Sum II
- LeetCode - Combination Sum II
- LeetCode:Combination Sum II
- 【Leetcode】Combination Sum II
- Combination Sum II 【leetcode】
- [LeetCode] Combination Sum II
- 【黑马程序员】分类与协议
- leetcode-20 Valid Parentheses
- 读《项目经理应该知道的97件事》
- 如何决定 Web 应用的线程池大小
- 使用jstl c:when报500的教训
- LeetCode Combination Sum II
- Message: Access to the registry key 'Global' is denied.
- 解决logstash1.4.2在windows上文件源读会对文件进行锁定的问题
- 最大网络最小流
- 杭电2564----词组缩写
- Xcode上传ipa时itunes提示you are not authorized to use this service
- leetcode之Repeated DNA Sequences
- Oracle EBS GL经常性日记帐(2)-复杂公式的设置和理解
- dll获得自身路径位置