leetcode之Repeated DNA Sequences

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用set去重复元素,最后 112 ms

class Solution:    # @param s, a string    # @return a list of strings    def findRepeatedDnaSequences(self, s):        d = {}        i = len(s)        l = []        index = 0        flag = False        if i < 10:            return l        else:            while index <= i - 10:                substr = s[index:index+10]                if d.has_key(substr):                    l.append(substr)                else:                    d[substr] = 1                index += 1        return list(set(l))


直接遍历的话, 99 ms

class Solution:    # @param s, a string    # @return a list of strings    def findRepeatedDnaSequences(self, s):        d = {}        i = len(s)        l = []        index = 0        flag = False        if i < 10:            return l        else:            while index <= i - 10:                substr = s[index:index+10]                if d.has_key(substr):                    for str in l:                        if str == substr:                            flag = True                            break                    if not flag:                        l.append(substr)                else:                    d[substr] = 1                index += 1        return l

但是每次运行时间也不太一样。。。不知道到底准不准


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