Search Insert Position - Leetcode

public class Solution {    public int searchInsert(int[] A, int target) {        int start = 0, end = A.length-1;int mid;        while(start<=end){            mid = (start+end)/2;            if(A[mid] == target)            return mid;            else if(target > A[mid])            start = mid+1;            else            end = mid-1;        }        return start;    }}

分析：返回的是插入的值，start的位置。

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

Here are few examples.
[1,3,5,6], 5 → 2
[1,3,5,6], 2 → 1
[1,3,5,6], 7 → 4
[1,3,5,6], 0 → 0